What is the magnitude of the electric field in which an electron experiences an electric force equal to its weight?
An electron experiences a force equal to its weight, when placed in an electric field. The intensity of the field will be 5.5 × 10–11 N/C.
What is the magnitude of an electric field in which the electric force?
The electric field E is defined to be E=Fq E = F q , where F is the Coulomb or electrostatic force exerted on a small positive test charge q. E has units of N/C. The magnitude of the electric field E created by a point charge Q is E=k|Q|r2 E = k | Q | r 2 , where r is the distance from Q.
What is the magnitude of an electric field which will balance the weight of an electron on the surface of Earth?
The Electric Field due to the electron is directed towards it (i.e. in -i direction) with magnitude 1.44*10^-5 N/m.
What is the magnitude of the electric field at one electron due to the other?
The magnitude of the electric field at one electron due to the other is 0.1625 N/C.
What charge is a proton?
Protons have a positive charge. Electrons have a negative charge. The charge on the proton and electron are exactly the same size but opposite. Neutrons have no charge.
What is the magnitude of the electric field intensity at a point where a proton experiences an electrostatic force of magnitude 2.30 x10 25 Newton?
What is the magnitude of the electric field intensity at a point where a proton experiences an electrostatic force of magnitude 2.30 x 10-25 newton? 144×10-25.
What is the magnitude of the electric field at the point?
the magnitude of the electric field (E) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation E = kQ/r2, where k is a constant with a value of 8.99 x 109 N m2/C2.
What is the magnitude and direction of the electric field?
The electric field direction points straight away from a positive point charge, and straight at a negative point charge. The magnitude of the electric field falls off as 1 / r 2 1/r^2 1/r21, slash, r, squared going away from the point charge.
What is the magnitude of the electric field of a proton?
Use 1.67×10−27 1.67 × 10 − 27 kg for the mass of a proton, 1.60×10−19 1.60 × 10 − 19 C for the magnitude of the charge on an electron, and 9.81 m/s2 for the magnitude of the acceleration due to gravity.
What is the magnitude of a proton?
Proton is the positively charged particle present in the nucleus of the atom. Magnitude of charge: Charge of proton is 1.6022 x 10-19 coulomb. Mass of proton: Mass of proton is 1.0072766 a.m.u. or 1.6726 x 10–27 kg.
What is the magnitude of the electrical force on the electron from the proton?
The electric force between two electrons is the same as the electric force between two protons when they are placed as the same distance.
|particle-particle||Fg (N)||Fc (N)|
|electron – proton||-1.0 x 10–47||– 2.3 x 10–8|
|electron – neutron||-1.0 x 10–47|
|proton – proton||– 1.9 x 10–44||2.3 x 10–8|
What is the magnitude of the electric field that will balance the weight of a proton?
What are the magnitude and direction of the electric field that will balance the weight of the following? For an electron/proton we use the equation qE=mg. Therefore the answer for magnitude would just to multiply the mass of an electron/proton by 9.8.
What is the defined mass of a proton?
proton, stable subatomic particle that has a positive charge equal in magnitude to a unit of electron charge and a rest mass of 1.67262 × 10−27 kg, which is 1,836 times the mass of an electron.
In which direction is the electric field?
Electric field is defined as the electric force per unit charge. The direction of the field is taken to be the direction of the force it would exert on a positive test charge. The electric field is radially outward from a positive charge and radially in toward a negative point charge.