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## What is the electric flux through a square?

Now, Gauss law states that electric flux through any closed surface is equal to the net charge enclosed inside the surface divided by the permittivity of vacuum. , where q is the net charge enclosed inside the surface. Now, we are given a charge placed at a distance of d/2 above the square of side ‘d’.

## What is the electric flux through the surface of the box?

– The net electric flux through the surface of a box is directly proportional to the magnitude of the net charge enclosed by the box. →net flux constant. -The net electric flux due to a point charge inside a box is independent of box’s size, only depends on net amount of charge enclosed.

## What is the electric flux through the area?

The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field. Gauss’s Law is a general law applying to any closed surface.

## How do you calculate electric flux?

Know the formula for electric flux.

- The Electric Flux through a surface A is equal to the dot product of the electric field and area vectors E and A.
- The dot product of two vectors is equal to the product of their respective magnitudes multiplied by the cosine of the angle between them.

## Is electric flux a vector?

As it is a dot product. So, electric flux is a scalar quantity. What are co-planar vectors?

## What is the ratio of electric flux through S1 and S2?

Answer: The ratio of electric flux through S1 and S2 = 1/3.

## What is the electric flux φ through each of the six faces of the cube?

The electric flux Φ through each of the six faces of the cube is (q/6ε_{}). B. Flux is independent of the dimension of an imaginary Gaussian surface. The flux Φ_{1} through a face of the cube if its sides were of length L_{1} is Φ_{1} = (q/6ε_{}).

## What is the flux through one face of the cube?

Gauss’s law tells that the total flux through an area enclosing a charge Q is Qε0. Now as the cube is having six faces and as we can assume a symmetrical distribution of fluxes among its faces, the flux associated with one of its faces is Q6ε0.

## What is the electric flux going through the top square face of the cube?

The electric flux through the top face (FGHK) is positive, because the electric field and the normal are in the same direction. The electric flux through the other faces is zero, since the electric field is perpendicular to the normal vectors of those faces.

## What is the dimension of electric flux?

Therefore, the electric flux is dimensionally represented as [M^{1} L^{3} T^{–}^{3} I^{–}^{1}].

## Does electric flux depend on area?

The numerical value of the electric flux depends on the magnitudes of the electric field and the area, as well as the relative orientation of the area with respect to the direction of the electric field. … The same number of field lines cross each surface.