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Considering a Gaussian surface in the form of a sphere at radius r > R, the electric field has the same magnitude at every point of the surface and is directed outward. The electric flux is then just the electric field times the area of the spherical surface.

## How do you calculate electric flux through A sphere?

Calculate (a) the magnitude of the electric field at any point on its surface, (b) the angle that the electric field at a point on the surface makes with normal to the surface at that point, and (c) the electric flux that passes through the entire surface of the sphere. (a) E = kq/r^{2} = {9.

## What is the electric flux through the sphere due to this charge?

This question already has an answer here:

According to Gauss’s law, the net flux through the sphere is zero because it contains no charge.

## How do you find electric flux through A surface?

The Electric Flux through a surface A is equal to the dot product of the electric field and area vectors E and A. The dot product of two vectors is equal to the product of their respective magnitudes multiplied by the cosine of the angle between them.

## What is flux in sphere?

Considering a Gaussian surface in the form of a sphere at radius r > R , the electric field has the same magnitude at every point of the surface and is directed outward. The electric flux is then just the electric field times the area of the spherical surface.

## What is the electric flux through?

Electric flux is the rate of flow of the electric field through a given area (see ). … For a non-uniform electric field, the electric flux dΦE through a small surface area dS is given by dΦE=E⋅dS d Φ E = E ⋅ d S (the electric field, E, multiplied by the component of area perpendicular to the field).

## What is the electric flux through a surface of a sphere due to a point charge lying outside it?

Answer: Zero. Explanation: According to gauss law, the net flux passing through a surface is proportional to the charge enclosed within the surface.

## What is the electric flux through the upper face of the box?

The electric flux through the top face (FGHK) is positive, because the electric field and the normal are in the same direction. The electric flux through the other faces is zero, since the electric field is perpendicular to the normal vectors of those faces.

## What is the electric flux through a closed surface enclosing an electric dipole?

“The net electric flux through any hypothetical closed surface is equal to 1ε0 times the net charge within that closed surface.” So, the net charge in the above question is zero. Electron dipole is a positive and negative charge of equal magnitude at a specific distance.