Quick Answer: What are the magnitude and direction of the electric field at a distance?

the magnitude of the electric field (E) produced by a point charge with a charge of magnitude Q, at a point a distance r away from the point charge, is given by the equation E = kQ/r2, where k is a constant with a value of 8.99 x 109 N m2/C2.

What is the magnitude and direction of an electric field?

The electric field direction points straight away from a positive point charge, and straight at a negative point charge. The magnitude of the electric field falls off as 1 / r 2 1/r^2 1/r21, slash, r, squared going away from the point charge.

IT\'S FUNNING:  What energy transformation occurs during the combustion of coal in a power plant?

What is the magnitude and direction of the electric field at point P?

The electric field at point P caused by each charge is equal in magnitude, but opposite in direction. Adding them together results in no net electric field at the centre point. Two charges Q and -Q are a distance L apart.

What is the magnitude of electric field?

The magnitude of the electric field is simply defined as the force per charge on the test charge. The standard metric units on electric field strength arise from its definition. Since electric field is defined as a force per charge, its units would be force units divided by charge units.

What is the magnitude and direction of the electric field at 0.25 m from a 6 C point charge?

We can find the magnitude of the electric field as follows: E = k ∣ q ∣ r 2 = 9 ⋅ 1 0 9 N m 2 C 2 ⋅ ∣ − 5.6 ⋅ 1 0 − 6 C ∣ ( 0.25 m ) 2 = 8.1 ⋅ 1 0 5 N C .

What is the magnitude of the electric field at the origin?

Therefore, the magnitude of the electric field at the origin is zero.

What is the direction of electric field?

Electric field is a vector quantity whose direction is defined as the direction that a positive test charge would be pushed when placed in the field. Thus, the electric field direction about a positive source charge is always directed away from the positive source.

What are the magnitude and direction of the electric field that will balance the weight of an electron?

Why is the direction of the electric field that will balance the weight of an electron downward, and a proton upward? – Physics Stack Exchange.

IT\'S FUNNING:  Question: How does Madhya Pradesh generate electricity?

What is the magnitude and direction of the electric force on an electron in a uniform electric field?

The electric field points due East and it has a magnitude 2,460 Newtons per Coulomb. This direction of electric field is the direction of force on a positive charge. Because this is an electron with negative charge, the direction of the force of this electric field applies on the electron will be to the left.

What is the magnitude and direction of the electric field 0.25 m from a x 10 6 C point charge?

A proton moves in a constant electric field E from point A to point B. The magnitude of the electric field is 4.2 x 10* N/C; and it is directed as shown in the drawing, the direction opposite to the motion of the proton.

What is the magnitude of the electric field at point P due to the two fixed charges as shown *?

The magnitude of electric field at point P due to the system of two charges as shown in figure is (K = 4. Odda se answer: Kq 1202.

What is the direction of the electric field at a point directly to the left of a positive charge?

The electric field points to the left because the force on a negative charge is opposite to the direction of the field. The electric field points to the right because the force on a negative charge is in the same direction as the field.

What is the direction of the electric field vector in a negative charge?

Given a point charge, or a particle of infinitesimal size that contains a certain charge, electric field lines emanate radially in all directions. If the charge is positive, field lines point radially away from it; if the charge is negative, field lines point radially towards it.

IT\'S FUNNING:  You asked: What is the magnitude of the electric field at location P?

How do you find the magnitude of the electric field strength?

The electric field E is defined to be E=Fq E = F q , where F is the Coulomb or electrostatic force exerted on a small positive test charge q. E has units of N/C. The magnitude of the electric field E created by a point charge Q is E=k|Q|r2 E = k | Q | r 2 , where r is the distance from Q.